if expression:
statement(s)a = 3 if a > 2: print(a, "is greater") print("done") a = -1 if a < 0: print(a, "a is smaller") print("Finish")
if test expression: Body of if stmts else: Body of else stmts
bp=int(input("Enter basic pay: ")); if bp >= 15000: np=bp+bp*.85; print("Net Pay= ",np); else: np=bp+bp*.5; print("Net Pay= ",np);
If test expression:
Body of if stmts
elif test expression:
Body of elif stmts
else:
Body of else stmtsn=int(input(“Enter any number:”)) if n<10: print(n,” is single digited”) elif n>9 and n<100: print(n,” is double digited”) elif n>99 and n<1000: print(n,” is triple digited”) else: print(n,” is multiple digited”)
a = float (input("Enter First Value: ")) b = float (input("Enter Second Value: ")) operator = input ("Enter Operator: ") if operator == '+': print ("Result= ", a+b) elif operator == '-': print ("Result= ", a-b) elif operator == '*': print ("Result= ", a*b) elif operator == '/': print ("Result= ", a/b) else: print ("Operator Doesn't Macth the Criteria ")
while(expression):
Statement(s)n = 50 while(n >=2 ): print(n) n =n-2
n=int(input("Enter a number")); c=0; while(n!=0): n=int(n/10); c=c+1; print("No. of Digits=",c);
n=int(input("Enter decimal number")); p=int(0); r=int(0); x=n; while n!=0: b=int(n/2); d=n-b*2; r=r+d*pow(10,p); p=p+1; n=b; print("Binary of",x," is ",r);
Step-by-Step Explanation of above code:
Step
1: n = int(input("Enter decimal
number"))
input("Enter decimal number"): This statement asking the user to enter a decimal number. Theinput()function waits for the user to enter a value.int(): Converts the input (which is a string) into an integer. So, whatever decimal number the user enters is converted into an integer and assigned to the variablen.
Step
2: p = int(0)
pis initialized to 0. It will be used as a position counter (starting from the rightmost bit) while constructing the binary number.
Step
3: r = int(0)
ris initialized to 0. This variable will hold the binary result. Initially, it is set to zero.
Step
4: x = n
xis a copy ofn, used to preserve the original decimal number. This will be used in the final print statement to show the original input.
Step
5: while n != 0:
- This
starts a
whileloop that runs as long asnis not equal to 0. - The
idea is to repeatedly divide the decimal number
nby 2 to get the binary digits.
Step
6: b = int(n / 2)
b = int(n / 2): This line dividesnby 2 (using integer division). It computes the quotient of the division, which represents the remaining number to process in the next iteration. This quotient is stored inb.
Step
7: d = n - b * 2
d = n - b * 2: This line calculates the remainder of the division, which is either 0 or 1. It's essentially the least significant bit (rightmost bit) of the binary number.- If
nis even,dwill be 0 (becausendivided by 2 leaves no remainder). - If
nis odd,dwill be 1 (becausendivided by 2 leaves a remainder of 1).
Step
8: r = r + d * pow(10, p)
pow(10, p): This line raises 10 to the power ofp. It is used here to place the bitdin the correct position in the binary number. For example, ifp = 0, it addsd * 1tor; ifp = 1, it addsd * 10(moving the bit one place to the left), and so on.r = r + d * pow(10, p): This adds the bitdto the current value ofr, shifting it appropriately by using powers of 10.
Step
9: p = p + 1
- This
line increments
pby 1, so the next bit will be placed in the next higher position in the binary number (next left bit).
Step
10: n = b
n = b: This line setsnto the quotientbfrom the division. The next iteration will now work with the smaller valueb, repeating the process untilnbecomes 0.
Step
11: print("Binary
of", x, "is", r)
- After
the
whileloop finishes (i.e., whennbecomes 0), the program prints the binary equivalent of the decimal numberx. The variablercontains the binary representation, and it's printed out as the result.
Example Walkthrough:
Let's say the user inputs n
= 10 (decimal number).
1.
First Iteration
(n = 10):
b = int(10 / 2) = 5(quotient)d = 10 - 5 * 2 = 0(remainder)r = 0 + 0 * pow(10, 0) = 0p = 1(incremented)n = 5(updated to quotient)
2.
Second Iteration
(n = 5):
b = int(5 / 2) = 2(quotient)d = 5 - 2 * 2 = 1(remainder)r = 0 + 1 * pow(10, 1) = 10p = 2(incremented)n = 2(updated to quotient)
3.
Third Iteration
(n = 2):
b = int(2 / 2) = 1(quotient)d = 2 - 1 * 2 = 0(remainder)r = 10 + 0 * pow(10, 2) = 10p = 3(incremented)n = 1(updated to quotient)
4.
Fourth Iteration
(n = 1):
b = int(1 / 2) = 0(quotient)d = 1 - 0 * 2 = 1(remainder)r = 10 + 1 * pow(10, 3) = 1010p = 4(incremented)n = 0(updated to quotient, loop ends)
After the loop, the program prints:
Binary of 10 is 1010
Conclusion:
This program converts a decimal number to binary by repeatedly dividing the
number by 2, storing the remainders (binary digits), and building the result.for value in sequence: {loop body}
n = 4 for i in range(0, n): print(i)
For i in range(10,0,-1): Print(i)
For i in range(20,1,-2): Print(i)
Step-by-Step Explanation:
Step
1: for i in range(20, 1, -2):
for i in ...: This line begins aforloop, which will iterate over a sequence of values. The variableiwill take on the value of each item in the sequence, one by one, for each iteration.range(20, 1, -2): This line generates a sequence of numbers using therange()function. It takes three arguments:- The
first argument (20) is the
starting value of the sequence. The loop will start with this value.
- The
second argument (1) is the
stopping condition. The loop will stop when the value reaches 1 (but it
will not include 1).
- The
third argument (-2) is the
step value, which indicates how much to decrease the value after each
iteration. In this case,
-2means that the value will decrease by 2 in each iteration (i.e., count backward by 2).
So,
range(20, 1, -2) generates the sequence:
20, 18, 16, 14, 12, 10, 8, 6, 4, 2. The loop will run for
each value in this sequence.
Step
2: print(i)
- This
line is the body of the
forloop. For each value ofi, it prints the value ofito the screen. - For
example, in the first iteration,
iwill be 20, soprint(i)will display20. In the next iteration,iwill be 18, and so on.
Summary:
- The
loop starts at 20 and counts down by 2 (i.e., 20, 18, 16, ...), stopping
just before it reaches 1.
- The
print(i)statement prints each value as the loop runs through the sequence generated byrange(20, 1, -2).
for outer_variable in range(start, stop): # Outer loop body for inner_variable in range(start, stop): # Inner loop body
· The outer
loop runs first and controls how many times the inner loop will execute.
· The inner
loop will execute completely for every iteration of the outer loop.
Summary:
- A nested loop is when you have one loop
inside another loop.
- The inner loop runs completely for every single
iteration of the outer loop.
- They are useful for iterating over
multi-dimensional data or performing tasks that require multiple
iterations.
for loopfor i in range(0, 6): for j in range(0, i+1): print("*", end=" ") print()
Step-by-Step Explanation:
Step 1: for
i in range(0, 6):
range(0, 6): Therange()function generates a sequence of numbers from 0 to 5 (inclusive of 0, exclusive of 6). This means the outer loop (i) will iterate 6 times, withitaking the values 0, 1, 2, 3, 4, and 5 in each iteration.- Outer loop: The variable
iwill represent the current row number in the pattern.
Step 2: for
j in range(0, i+1):
- Inner loop: For each iteration of the outer loop, we have an inner loop.
range(0, i+1): This creates a sequence of numbers from 0 toi, inclusive. Thei+1ensures that the inner loop runs for exactlyi + 1iterations. This means the number of stars printed in each row depends on the value ofi.- When
i = 0, the inner loop will run0 + 1 = 1time. - When
i = 1, the inner loop will run1 + 1 = 2times, and so on.
Step 3: print("*",
end=" ")
print("*", end=" "): This prints a star (*) followed by a space.end=" ": By default, theprint()function ends with a newline (\n). Here,end=" "changes the behavior, so it adds a space (" ") after each star instead of moving to the next line. This ensures that the stars in each row are printed on the same line, separated by a space.
Step 4: print()
print(): After the inner loop finishes running, thisprint()function is called without any arguments. This prints a newline character (\n), causing the next set of stars to appear on a new line. This happens after the stars for each row are printed.
Summary:
- The outer loop (for i in range(0, 6)) controls how many rows of
stars will be printed.
- The inner loop (for j in range(0, i+1)) controls how many stars will
be printed in each row.
- The print("*", end=" ") statement prints a star
followed by a space, keeping the stars on the same line.
- After each row is printed, the print() statement adds a new line to
separate the rows.
This code will print a right-angled triangle pattern of stars, where the number of stars increases by 1 with each row.
Nested while loop
Preview:
i = 1 while i <= 6: # Outer while loop j = 1 while j <= i: # Inner while loop print("*",end = " ") j += 1 print() i += 1
# Example 1 of Nested For Loops (Pattern Programs)
for i in range(1,6): for j in range(0,i): print(i, end=" ") print('')
Output:
2 2
Break and continue:
Break:
for var in sequence: # code inside for loop If condition: break (if break condition satisfies it jumps to outside loop) # code inside for loop # code outside for loop
for num in [11, 9, 88, 10, 90, 3, 19]: print(num) if(num==88): print("The number 88 is found") print("Terminating the loop") break
Output:
11
The following shows the working of break statement in for and while loop:
while test expression # code inside while loop If condition: continue (if continue condition satisfies it jumps to outside loop) # code inside while loop # code outside while loop

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